Two resistors, 400 Ω Ω , and 800 Ω Ω are connected in series with a 6 V battery. It is desired to measure the current in the circuit. An ammeter of 10 Ω Ω resistance is used for this purpose. The reading of ammeter will be 
A. Similarly, if a voltmeter of 1000 Ω Ω resistance is used to measure the potential difference across the 400 Ω Ω resistor, the reading of voltmeter is 
V. Then the value of N and P are:
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(N = 6 and P = 30)
Sol.
Refer figure : Current through ammeter,
i = 
= 
= 4.96 × 10 –3 A
= 4.96 mA
Refer figure : Combined resistance of 1000 Ω Ω voltmeter and 400 Ω Ω resistance is,
R = 
= 285.71 Ω Ω
i = 
= 5.53 × 10 –3 A
Reading of voltmeter
= V ab = iR = (5.53 × 10 –3 ) (285.71)
= 1.58 volt
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